0=-16t^2+7000

Solution for 0=-16t^2+7000 equation:

0=-16t^2+7000

We move all terms to the left:

0-(-16t^2+7000)=0

We add all the numbers together, and all the variables

-(-16t^2+7000)=0

We get rid of parentheses

16t^2-7000=0

a = 16; b = 0; c = -7000;
Δ = b2-4ac
Δ = 02-4·16·(-7000)
Δ = 448000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448000}=\sqrt{6400*70}=\sqrt{6400}*\sqrt{70}=80\sqrt{70}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{70}}{2*16}=\frac{0-80\sqrt{70}}{32}
=-\frac{80\sqrt{70}}{32}
=-\frac{5\sqrt{70}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{70}}{2*16}=\frac{0+80\sqrt{70}}{32}
=\frac{80\sqrt{70}}{32}
=\frac{5\sqrt{70}}{2}
$